2n^2+3n-8=-8n^2

Solution for 2n^2+3n-8=-8n^2 equation:

2n^2+3n-8=-8n^2

We move all terms to the left:

2n^2+3n-8-(-8n^2)=0

We get rid of parentheses

2n^2+8n^2+3n-8=0

We add all the numbers together, and all the variables

10n^2+3n-8=0

a = 10; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·10·(-8)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{329}}{2*10}=\frac{-3-\sqrt{329}}{20}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{329}}{2*10}=\frac{-3+\sqrt{329}}{20}
$